Number Series


1.

Choose the correct alternative that will continue the same pattern and replace 'x' in series 6,18,42,78,x
 

A. 84
B. 126
C. 96
D. 108

Option B

 The pattern is +12,+24,+36,+48, . . . .
 So,missing term=78+48=126
 

2.

Find the wrong number in the following series?1500, 1475, 1448, 1419, 1389, 1355, 1320
 

A. 1475
B. 1419
C. 1389
D. 1355

Option C

1389 is wrong one. It should be 1388.
 

3.

Choose the correct alternative that will continue the same pattern and replace 'x' in the series 3,12,27,48,75,x,147

A. 108
B. 127
C. 112
D. 85

Option A

The terms of the given series are 3*(1*1),3*(2*2),3*(3*3),3*(4*4), . . . .
So,missing term is 3*(6*6)=108
 

4.

Choose the correct alternative that will continue the same pattern and replace 'x' in given series 1,2,6,15,31,56,x

A. 65
B. 78
C. 81
D. 92

Option D

The pattern is + 1*1,+ 2*2, +3*3, + 4*4,+ 5*5,+ 6*6, . . . . . . .
So missing term is 56+36=92

5.

Find out the wrong term in the series 83,92,85,90,85,88

A. 85
B. 88
C. 90
D. 92

Option A

The correct pattern is +9,-7,+5,-3,+1
So,85 is wrong term and must be replaced by 90-3=87

6.

bc _ b _ c _ b _ ccb

A. c b c b
B. b b c b
C. c b b c
D. b c b c

Option A

Here e 'bccb' repeated 3 times.b c c b | b c c b | b c c b 

7.

In the following question a letter-series is given, in which some letters are missing. The missing letters are given in the proper sequence as one of the alternatives. Choose the correct alternatives. ab __ d __ aaba __ na _ badna _ b
 

A. Andaa
B. babda
C. dbanb
D. badna

Option A

The series is abadna/abadna/abadna/ab.
The pattern 'abadna' is repeated

8.

Choose the correct alternative that will continue the same pattern and replace 'x' in the series 6834,6151,5536,4983,x

A. 4467
B. 4538
C. 4184
D. 4485

Option D

Each term in the series is obtained by subtracting from the preceding term the number formed by the first three digits of preceding term
So,missing term is 4983-498=4485
 

9.

Find the wrong number in the series.1, 2, 6, 15, 31, 56, 91

A. 31
B. 15
C. 56
D. 91

Option D

The difference of the two consecutive numbers are 1, 4, 9, 16, 25, 35.This is clearly , Here 35 is wrong, So our wrong number is 91
 

10.

Find the missing number in the following series       
   512, 256, 64, 32, ?

A. 16
B. 4
C. 8
D. 10

Option C

512/2 = 256

256/4 = 64

64/2 = 32

32/4 = 8.
 

11.

Look at this series: 31, 29, 24, 22, 17, . . . 
What number should come next?

A. 15
B. 14
C. 13
D. 12

Option A

This is a simple alternating subtraction series, which subtracts 2, then 5.

Rule = (first number - 2) (second number - 5) (third number - 2) (fourth number - 5)...

Now The series is 31, 29, 24, 22, 17, . . .

(31 - 2 = 29), (29 - 5 = 24), (24 - 2 = 22), (22 - 5 = 17), (17 - 2 = 15)...

So the answer is a = 15.
 

12.

Look at this series: 14, 28, 20, 40, 32, 64, . . .

 What number should come next ?
 

A. 52
B. 56
C. 86
D. 98

Option B

This is an alternating multiplication and subtracting series: First, multiply by 2 and then subtract 8.

Rule = (1st no.) (1st x 2 = 2nd no.) (2nd - 8 = 3rd no.) (3rd x 2 = 4th no.)....

Now (14) (14 x 2 = 28) (28 - 8 = 20) (20 x 2 = 40) (40 - 8 = 32) (32 x 2 = 64) (64 - 8 = 56)...

So the answer is b = 56.
 

13.

1, 2, 3, 10, ____, 9802

A. 199
B. 999
C. 99
D. 298

Option C

12 + 1 = 2

22 - 1 = 3

32 + 1 = 10

102 - 1 = 99.
 

14.

18 21 25 18 29 33 18

What numbers should come next ?
 

A. 43 18
B. 41 44
C. 37 41
D. 38 41

Option C

This is a simple addition series with a random number, 18, interpolated as every third number.
 

15.

In the series, 4 is added to each number except 18, to arrive at the next number. 3, 9, 21, ___, 93
3, 9, 21, ___, 93

A. 36
B. 45
C. 47
D. 51

Option B

First difference is 6 and second is 12.

But if we take third as 18, then fourth difference will be 24.

Then 93 can not be the last term.

So we have to take the difference as 6, 12, 24 and 48.

So 21 + 24 = 45.
 

16.

Which is the number that comes next in the sequence :
0, 6, 24, 60, 120, 210 ?
 

A. 240
B. 290
C. 336
D. 504

Option C

Clearly, the given series is 13 - 1, 23 - 2, 33 - 3, 43 - 4, 53 - 5, 63 - 6.
 Next number = 73 - 7 = 343 - 7 = 336.
 

17.

How many terms are there in the series 201, 208, 215, ..., 369 ?
 

A. 23
B. 24
C. 25
D. 26

Option C

(Use Arithmetic Progression)
The given series is an A.P. in which a = 201 and d = 7.
Let the number of terms be n.
Then, 369 = 201 + (n - 1) x 7 or  n = 25.
 

18.

Look at this series: 544, 509, 474, 439, . . .
What number should come next?
 

A. 420
B. 445
C. 404
D. 414

Option C

This is a simple subtraction series.
Each number is 35 less than the previous number.
(544 - 35 = 509) (509 - 35 = 474) (474 - 35 = 439) (439 - 35 = 404
 

19.

Look at this series: 2, 4, 6, 8, 10, . . . 
What number should come next ?
 

A. 11
B. 12
C. 13
D. 14

Option B

This is a simple addition series.
Each number increases by 2.
Like -
First number is 2
Second number = 2 + 2 =4
Third number = 4 + 2 = 6
Fourth number = 6 + 2 = 8
Fifth number = 8 + 2 = 10  and
Sixth number = 10 + 2 = 12
 

20.

Find the wrong number in the series :
3, 8, 15, 24, 34, 48, 63
 

A. 15
B. 24
C. 34
D. 48

Option C

The difference between consecutive terms of the given series are respectively 5, 7, 9, 11 and 13.
Clearly, 34 is a wrong number and must be replaced by (24 + 11) i.e. 35.
Hence, the answer is (c).
 

21.

Look at this series: 80, 10, 70, 15, 60, . . . 
What number should come next?
 

A. 20
B. 25
C. 30
D. 35

Option A

This is an alternating addition and subtraction series.
In the first pattern, 10 is subtracted from each number to arrive at the next.
In the second, 5 is added to each number to arrive at the next.
First pattern (80) (80 - 10 = 70) (70 - 10 = 60) (60 - 10 = 50)
Second pattern (10) (10 + 5 = 15) (15 + 5 = 20)
So the answer is a = 20.
 

22.

Look at this series: 8, 22, 8, 28, 8, . . .
What number should come next ?
 

A. 9
B. 29
C. 32
D. 34

Option D

This is a simple addition series with a random number, 8, interpolated as every other number.
In the series, 6 is added to each number except 8, to arrive at the next number.
In this Series 8 is common number.
Now add 6 with 22 or 28.
22 + 6 = 28
28 + 6 = 34.
So the answer is d = 34.
 

23.

Look at this series: 2, 6, 18, 54, . . .
What number should come next?
 

A. 162
B. 216
C. 148
D. 108

Option A

This is a simple multiplication series. 
Each number is 3 times more than the previous number.
The series is 2, 6, 18, 54, . . .
Rule = (1st number x 3 = 2nd number) (2nd number x 3 = 3rd number)....
Now (2) (2 x 3 = 6), (6 x 3 = 18), (18 x 3 = 54) (54 x 3 = 162)...
So the answer is c = 162.
 

24.

13, 39, 118, 356, 1071, 3217, __
 

A. 9656
B. 6459
C. 6355
D. 9651

Option A

13*3+0, 39*3+1, 118*3+2, 356*3+3, 1071*3+4, 3217*3+5, __
The next number in the series is 3217 * 3 + 5 = 9656.
 

25.

12, 35, 106, 317, 952, __

A. 2851
B. 2855
C. 1851
D. 1849

Option B

12*3 - 1, 35*3 + 1, 106*3 - 1, 317*3 + 1, 952, __The next number in the series is 952 * 3 - 1 = 2855.
 

26.

In the series 3, 9, 15, ...... what will be the 21st term?

A. 117
B. 121
C. 123
D. 129

Option C

Clearly, 3 + 6 = 9, 9 + 6 = 15,.....
So, the series is an A.P. in which a = 3 and d = 6.
Therefore 21st term = a + (21 - 1) d = a + 20d = 3 + 20 x 6 = 123.
 

27.

13, 35, 57, 79, 911, ?

A. 1110
B. 1112
C. 1113
D. 1315

Option C

The terms of the given series are numbers formed by joining together consecutive
odd numbers in order i.e. 1 and 3, 3 and 5, 5 and 7, 7 and 9, 9 and 11, .....
So, missing term = number formed by joining 11 and 13 = 1113.
 

28.

3, 15, ?, 63, 99, 143
 

A. 27
B. 35
C. 45
D. 56

Option B

The terms of the given series are (22 - 1), (42 - 1),....., (82 - 1), (102 - 1), (122 - 1).
So, missing term = (62 - 1) - (36 - 1) = 35.
 

29.

Which term of the series 5, 10, 20, 40, ..... is 1280?
 

A. 10th
B. 9th
C. 8th
D. None of these

Option B

Clearly, 5 x 2 = 10, 10 x 2 = 20, 20 x 2 = 40,.....
So, the series is a G.P. in which a = 5 and r = 2.
Let 1280 be the rath term of the series.
Then, 5x2n-1 = 1280 2n-1 = 256 = 28 n - 1 = 8 n = 9.
 

30.

JTU, __, UCF, BFM, JHU

A. OYZ
B. JCZ
C. OCF
D. JCZ

Option A

The given series is a mixed series. Pattern for the first letter:J+5, O+6, U+7, B+8, J Pattern for the second letter:T+5, Y+4, C+3, F+2, H Pattern for the third letter:U+5, Z+6, F+7, M+8, U Hence, the missing group in OYZ

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